0=d^2-14d+24

Solution for 0=d^2-14d+24 equation:

0=d^2-14d+24

We move all terms to the left:

0-(d^2-14d+24)=0

We add all the numbers together, and all the variables

-(d^2-14d+24)=0

We get rid of parentheses

-d^2+14d-24=0

We add all the numbers together, and all the variables

-1d^2+14d-24=0

a = -1; b = 14; c = -24;
Δ = b2-4ac
Δ = 142-4·(-1)·(-24)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*-1}=\frac{-24}{-2}
=+12
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*-1}=\frac{-4}{-2}
=+2
$